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• Let me add, let me make it 17 people so we have an odd number, so go and sit in that row.

我再加一个人这样就是奇数17个人,请到那行中

耶鲁公开课 - 博弈论课程节选

• so given that we chose an odd number of people in the row, if exactly one candidate stands and that candidate is the center candidate, then that's an equilibrium.

假若我们选中行的人数为奇数,如果确实只有一个候选人参选且,那个候选人就是在中间,则那是个均衡

耶鲁公开课 - 博弈论课程节选

• The number 3 is an odd number.

是一个奇数。

耶鲁公开课 - 死亡课程节选

• In either case, I take that value and multiply back by two, if it was even I get back the original number, if it was odd, I'm not going to get back the original number, so I can just check to see if they're the same.

在两种情况中，我都把结果值,再乘以2，如果x是偶数我就,得到了原来的值，如果x是奇数那么就不会得到,原来的值，因此我看看得到的值,和原来的值相等不相等就可以了。

麻省理工公开课 - 计算机科学及编程导论课程节选

• It's eternally an odd number.

它永远是个奇数。

耶鲁公开课 - 死亡课程节选

• Claire Elise is going to get her own vote plus 1, 2, 3, 4, 5, 6, 7, 8, 8 votes and Beatrice is getting 1, 2, 3, 4, 5, 6, 7, how did I end up with eight, I thought I had an odd number. 1, 2, 3, 4, 5, 6, 7 there must have been an odd number before.

克莱尔·伊莉斯将获得自己的选票加上,12345678 8张选票,而比阿特丽斯获得1234567,我怎么数出8个来的,我想应该是个奇数,1234567,之前也应该是个奇数

耶鲁公开课 - 博弈论课程节选

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