But then, I combine i times Ax with i times Bx, because that's the vector parallel to i, with the length Ax.

然后我把 i ? Ax 和 i ? Bx 加起来,因为这是平行于 i,模长为 Ax 的矢量

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That's clear. If I add them, I'll get a vector parallel to i with lengths Ax + Bx.

这很明显 如果把他们加起来,就得到一个平行于 i,模长为 Ax + Bx 的矢量

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That would come by saying, "I'm taking i times Ax + j times Ay + i times Bx + j times By, " and I'm trying to add all these guys.

那就这样做,"i ? Ax + j ? Ay + i ? Bx + j ? By",然后把它们都加起来

耶鲁公开课 - 基础物理课程节选

That's the vector parallel to i, with length Bx.

这个是平行于 i,模长为 Bx 的矢量

耶鲁公开课 - 基础物理课程节选

A very important result is that if two vectors are equal, if A = B, the only way it can happen is if separately Ax is equal to Bx and Ay is equal to By.

这里有一个相当重要的结论,如果两个矢量相等,例如 A = B,那么当且仅当,Ax = Bx 和 Ay = By 分别成立

耶鲁公开课 - 基础物理课程节选