And note that as Z increases, as the proton number increases the radius decreases for a given n number.
并注意到当Z不断增加,对于一个给定的n,即当质子数增加的时候,半径的n值就减小了。
So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.
这里不再等于-z的平方,现在我们等于-有效的z的平方,乘以RH除以n的平方。
So we are going to put atomic hydrogen Z equals one, 1 ground state n equals one.
氢原子Z等于,基态n也等于。
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