z So what we end up seeing is 34 that the z effective is equal to positive 1 . 3 4.
看到有效的,等于+1。
+4 Because this could be three plus four, 3 times five, or it could be three, plus four times five.
因为这可能是,然后乘以5,也可能是,加上4乘以5。
First of all, it's clear from the Pythagoras' theorem that a is the square root of ^2 + ^2.
首先,根据毕达哥拉斯定理,勾股定理在西方被称为"毕达哥拉斯定理"
du=dq+dw So our first law, du is dq plus dw.
热力学第一定律。
Well, we would have to H+ have one of these hydrogen atoms go to an H plus, * plus an electron, right? **H --> H+ + e-** So, now we have a hydrogen ion here.
我们先要让,一个氢原子变成氢离子,加上一个电子,对么*,我们现在有一个氢离子了。
z So in our first case, our first extreme case, would be that the z effective that is felt by electron number 1, is going to be plus 1.
被1号电子感知到的有效的,是+1所以,我们所能做的是计算出,我们从这个。
So this plus plus is sort of shorthand notation for incrementation. So just add 1 to this variable's value, so now socks on feet is of course 1 and so next.
那么这个++符号是递增排序的,所以仅仅是对这个变量加一,现在袜子在脚上是一,那么下一个也是这样。
The return on the portfolio is x1 r1 + x2 r2 + x3 r3.
这个投资组合的收益是。
When we say that 2 + 2 = 4 or 2 + 3 = 5, we're saying something about numbers that our mind is able to grasp.
当我们说2+2=4或2+3=5时,我们是在讨论心灵可以掌握的数字
I mean if you chose Alpha, you're swinging from A to B-; and from Beta, swinging from B+ to C.
要是你选α,你的分数会在A到B-,选β,分数范围会在B+到C
Because the B+ or A- people, B- you know it, they'll hire B's and B minuses.
原本想要B+或者A-的人,实际能力评分只有B或者。
Well, that then says after another 12 steps, 12+12+t we're down to a problem with size t of b over 4.
更进一步,也就是。
But it really wasn't until, I would say, the arrival of Java that object-oriented C++ programming caught the popular attention.
但是知道Java的诞生,才吸引了大众的关注,而后Java和。
And so what I get is the energy of the system at the equilibrium separation is given by minus z plus.
这就是通过减去z+得到得平衡分离时,我得到的能量体系。
It's going to be the same temperature V+dV as before but the volume is V plus dV now.
将升温到跟路径1的结果一样,但是现在的体积是。
counter++ So everything is kind of coming together now with then the counter ++.
只需要一个,所有的准备工作都做好了。
That means ^2 + ^2 = ^2 + ^2.
也就是 ^2 + ^2 = ^2 + ^2
So if we have total +2 and complete shielding -1 where that can actually negate a full positive charge, because remember our nucleus is plus 2, +1 one of the electrons is minus 1, so if it totally blocks it, all we would have left from the nucleus is an effective charge of plus 1.
抵消一个完全的正电荷,因为记住我们的原子核是,其中一个电子是,所以如果它完全挡住了它,我们从原子核中留下的,全部有效电荷就是,所以,在我们的第一个例子中,我们的第一种极端情况。
This number always lies between -1 and +1.
这个数的取值在-1到+1之间
And that makes sense, too, because the positive three pulling on minus one has a tighter binding energy than positive one pulling on minus one.
而这也是有意义的,因为+3和-1的相互吸引,产生了比+1和-1的吸引,更强的能量。
J++ Now here's the semicolon, J less than N, where N is this, J plus, plus; so what am I doing?
现在这里是一个分号,J小于N,N是这个,那么我在做什么?
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